I am using regex in GNU bash, version 4.4.23(1)-release (x86_64-pc-msys) (git bash).

I am having an issue indicating a colon to the regex.

I am looking for the following string:

Date : 25 Dolahn(6)

Using the following regex:

if [[ "$_line" =~ Date : (.*) ]]; then
    echo $_line
    _date=${BASH_REMATCH[1]}
fi

I get the following error:

parse.sh: line 47: syntax error in conditional expression
parse.sh: line 47: syntax error near `:'
parse.sh: line 47: `        if [[ "$_line" =~ Date : (.*) ]]; then'

According to this short answer, there is no escaping necessary for a colon (and it throws the same error anyway).

I also tried putting it into "[]", with the same error.

What am I doing wrong with this regex ? How do I indicate the colon ?