I had a bug with the following code and figured out the reason:

myset = set(["A", "C", "B"])

# Original Code: Fails  output: None
print(list(myset).sort())

list.sort() is an inplace sort with no return value, and this is passing the return from the sort() call to print; which is why this code doesn't work.

To fix it, I can obviously use the sorted function or write my own:

# Method 1: Works out: ['A', 'B', 'C']
print(sorted(myset))

# Method 2: Works out: ['A', 'B', 'C']
def mysetsort(s):
  l = list(s)
  l.sort()
  return l

print(mysetsort(s))

is there any way to do this along the lines of the original buggy inline implementation? ie use sort() on the temporary list from the cast, but pass in/return the temporary (sorted) object?

I'm kind of expecting the answer no, but I'm still learning python.

Thx