remove() and 'not in' function not working together
a = [1, 2, 3, 4, 5, 6, 7, 8]
b = [2, 4, 6]
for item in a:
if item not in b:
a.remove(item)
print(a)
This should return [2, 4, 6],
but instead returns [2, 4, 6, 8]
I thought it might be an indexing error under the hood, but:
a = [1, 2 3, 4, 5, 6, 7, 8, 10]
b = [2, 4, 6]
for item in a:
if item not in b:
a.remove(item)
print(a)
This ALSO returns [2, 4, 6, 8]
How?