From my MVC application, I am trying to make a POST request to these sample end-points (actions) in an API controller named MembershipController:
[HttpPost]
public string GetFoo([FromBody]string foo)
{
return string.Concat("This is foo: ", foo);
}
[HttpPost]
public string GetBar([FromBody]int bar)
{
return string.Concat("This is bar: ", bar.ToString());
}
[HttpPost]
public IUser CreateNew([FromBody]NewUserAccountInfo newUserAccountInfo)
{
return new User();
}
Here's the client code:
var num = new WebAPIClient().PostAsXmlAsync("api/membership/GetBar", 4).Result;
And here's the code for my WebAPIClient class:
public class WebAPIClient
{
private string _baseUri = null;
public WebAPIClient()
{
// TO DO: Make this configurable
_baseUri = "http://localhost:54488/";
}
public async Task PostAsXmlAsync(string uri, T value)
{
using (var client = new HttpClient())
{
client.BaseAddress = new Uri(_baseUri);
client.DefaultRequestHeaders.Accept.Clear();
client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/xml"));
var requestUri = new Uri(client.BaseAddress, uri);
var response = await client.PostAsXmlAsync(requestUri, value);
response.EnsureSuccessStatusCode();
var taskOfR = await response.Content.ReadAsAsync();
return taskOfR;
}
}
}
I have the following default route defined for the Web API:
config.Routes.MapHttpRoute(
name: "DefaultApi",
routeTemplate: "api/{controller}/{action}/{id}",
defaults: new { id = RouteParameter.Optional }
UPDATE
My code breaks into the debugger until the time the PostAsXmlAsync method on the System.Net.HttpClient code is called. However, no request shows up in Fiddler.
However, if I try to compose a POST request in Fiddler or try to fire a GET request via the browser to one of the API end-points, the POST request composed via Fiddler tells me that I am not sending any data and that I must. The browser sent GET request rightly tells me that the action does not support a GET request.
It just seems like the System.Net.HttpClient class is not sending the POST request properly.