How to display current logged-in user's information in all templates including view managed by WebMvcConfigurerAdapter in Spring Security application
11:51 29 Jan 2016

I have a Spring Boot application that uses Spring Security and Thymeleaf template. I am trying to display the logged-in user's first name and last name in a template when the controller is managed by a subclass of WebConfigurerAdapter.

So, say my WebConfigurerAdapter subclass looks like this

@Configuration
public class MvcConfig extends WebMvcConfigurerAdapter{

    @Override
    public void addViewControllers(ViewControllerRegistry registry){
        registry.addViewController("/some-logged-in-page").setViewName("some-logged-in-page");
        registry.addViewController("/login").setViewName("login");

    }
    ....
}

My User entity class looks like this

@Entity
@Table(name = "user")
public class User {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "id", nullable = false, updatable = false)
    private Long id;



    @Column(name="first_name", nullable = false)
    private String firstName;


    public String getFirstName() {
        return firstName;
    }
    ...
}

In my template, I have tried using code like

But it didn't work.

I know it is possible to use a ControllerAdvise as follows:

@ControllerAdvice
public class CurrentUserControllerAdvice {
    @ModelAttribute("currentUser")
    public UserDetails getCurrentUser(Authentication authentication) {
        return (authentication == null) ? null : (UserDetails) authentication.getPrincipal();
    }
}

and then access the details in the template using code like:


But this doesn't work with any view controller registered with my class MvcConfig. Rather I will need to make sure each of my controllers are separate classes.

So, could someone kindly point me to a way to automatically insert the logged-in user details to my view, e.g. some-logged-in-page.html in this example? Thanks

java spring spring-mvc spring-security thymeleaf