return one row for each Job_ID with the following columns:
• Job ID
• Average female service length in that job in years rounded to the tenth of a year
• Average Female Salary for that job
• Average male service length in that job in years rounded to the tenth of a year
• Average Male Salary for that job
• The difference in average male and female salaries for that job such that a positive number means the average female salary is higher and negative number means the average male salary is higher.
TABLE
HR.EMPLOYEES
Name Null Type
-------------- -------- ------------
EMPLOYEE_ID NOT NULL NUMBER(6)
FIRST_NAME VARCHAR2(20)
LAST_NAME NOT NULL VARCHAR2(25)
EMAIL NOT NULL VARCHAR2(25)
PHONE_NUMBER VARCHAR2(20)
HIRE_DATE NOT NULL DATE
JOB_ID NOT NULL VARCHAR2(10)
SALARY NUMBER(8,2)
COMMISSION_PCT NUMBER(2,2)
MANAGER_ID NUMBER(6)
DEPARTMENT_ID NUMBER(4)
GENDER CHAR(1)
What I Have So Far but this is returning an M & F row for each job_id i need M & F columns
SELECT gender, job_id, ROUND(AVG(salary),0) as avg_job_salary,
(SELECT ROUND(AVG(salary),0)
FROM hr.employees
WHERE gender = 'M') AS avg_m_salary, (SELECT ROUND(AVG(salary),0)
FROM hr.employees
WHERE gender = 'F') AS avg_f_salary,
ROUND(AVG(days_of_svc/365),1) AS avg_years_svc
FROM (SELECT job_id, salary, gender, (SYSDATE-hire_date) AS days_of_svc
FROM hr.employees)
GROUP BY job_id,gender
ORDER BY job_id, gender;
or version 2
SELECT gender, job_id, ROUND(AVG(salary),0) as avg_job_salary,
((SELECT ROUND(AVG(salary),0)
FROM hr.employees
WHERE gender = 'F') - (SELECT ROUND(AVG(salary),0)
FROM hr.employees
WHERE gender = 'M')) as diff,
ROUND(AVG(days_of_svc/365),1) AS avg_years_svc
FROM (SELECT job_id, salary, gender, (SYSDATE-hire_date) AS days_of_svc
FROM hr.employees)
GROUP BY job_id,gender
ORDER BY job_id, gender;
sample expected results rows
JOB_ID F_AVG_LENGTH F_AVG_SAL M_AVG_LENGTH M_AVG_SAL DIFFERENCE
------ ------------ --------- ------------ --------- ----------
MAILCLERK 24.1 48000 23.4 47000 1000
CASHIER 4.6 12000 4.4 13500 -1500