Ok I feel spechul for even asking, but I have tried several iterations of this and nothing has worked except hard coding the scriptname in the Scriptblock statement, which is unacceptable.

Here is the code that works, hard coded, unacceptable:

$Scriptblock = { C:\Scripts\Path1\ScriptName.ps1 -argument0 $args[0] -argument1 $args[1] }
Start-Job -ScriptBlock $Scriptblock -ArgumentList $argue0, $argue1 | Out-Null

I've tried this, and it doesn't work:

$loc = (Get-Location).Path
Set-Location -Path  $loc

And this:

$rootpath = $MyInvocation.MyCommand.Path.Substring(0, ($MyInvocation.MyCommand.Path).LastIndexOf("\"))
Set-Location -Path  $rootpath

And this:

$rootpath = $MyInvocation.MyCommand.Path.Substring(0, ($MyInvocation.MyCommand.Path).LastIndexOf("\"))
$scriptFilename = $([string]::Format("{0}\ScriptName.ps1", $rootpath))
$sb = $([string]::Format("{0} -arguement0 $args[0] -arguement1 $args[1]", $scriptFilename))
$Scriptblock = { $sb }
Start-Job -ScriptBlock $Scriptblock -ArgumentList $argue0, $argue1 | Out-Null   

Nothing else has worked except the first code above with hardcoded path and script name - I know it has to be something stupid I am missing - help me fix stupid please! ;-)